Chemistry, 14.06.2020 01:57 aide1234564

Which functional group is found in methyl ethanoate? A central carbon is double bonded to O above, and single bonded to R below left and to R below right.

A central carbon is double bonded to O above, and single bonded to R below left and to O R prime below right.

A central carbon is double bonded to O above, and single bonded to R below left and to H below right.

A carbon is bonded to R to the left, C O O H above right, H to the right, and N H 2 below right.

Answers: 3

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Answers

In the structure of methyl ethanoate, the O has a double bond with central carbon and is attached with the R group on the left, and with R prime on right with O. Thus, option B is correct.

Methyl ethanoate has been the organic compound with ester functional group as R-COO-R. The compound has been found to be present with the methyl as an R group, and another R group has been methyl. The functional group COO has been responsible for the reactivity of the compound.

The structure of methyl ethanoate has been shown in the image attached.

It has been consisted of an ester bond having central carbon attached to the O above with a double bond. It has the presence of a single R (methyl group) left to carbon, and R prime (methyl group) right to O. Thus, option B is correct.

For more information about methyl ethanoate, refer to the link:

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Answer from: princess5964

A central carbon is double bonded to O above, and single bonded to R below left and to O R prime below right.

Explanation:

Methyl ethanoate belongs to a homologous series in organic chemistry known as esters. A homologous series simply means a family of organic compounds. They always have the the same functional group and differ from each other by -CH2-functional group. The functional group is responsible for the chemical reactivity of the members of a particular homologous series.

The general formula for esters is RCOOR. Note that R and R may be the same or different. Hence, we have a central carbon atom, double bonded to an oxygen atom and also single bonded to R and OR respectively.

Which functional group is found in methyl ethanoate?

A central carbon is double bonded to O above,

Answer from: Quest

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Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

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Which functional group is found in methyl ethanoate? A central carbon is double bonded to O above,...