A 47L bottle of hydrogen peroxide will eventually decomposes into water and oxygen at SATP if the lid is left open, what concentration of hydrogen peroxide is required to react 8.42L of oxygen?

0.01596 M

Explanation:

This is a stoichiometry problem hence we need to obtain the balanced reaction equation before we can effectively proceed in solving the problem at hand.

Given the reaction equation;

2H2O2(aq) > 2H2O(l) + O2(g)

2 moles of hydrogen peroxide yields 1 mole of oxygen

I mole of oxygen occupies 22.4 L volume.

Hence

2 moles of hydrogen peroxide produces 22.4 L of oxygen

x moles of hydrogen peroxide produces 8.42 L of oxygen

x= 2 × 8.42/22.4

x= 0.75 moles of hydrogen peroxide

From

Number of moles = concentration × volume

Number of moles= 0.75 moles

Volume = 47 L

Concentration of hydrogen peroxide= number of moles/ volume

Concentration of hydrogen peroxide= 0.75 moles/47 L

Concentration of hydrogen peroxide= 0.01596 M

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