What mass of copper is required to completely replace silver from 4.00g of silver nitrate dissolved in water by the reaction cu(s) + 2 agno3 → cu(no3)2 + 2 ag.

Mass of copper is required to completely replace silver = 0,7493 grams

Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements, etc.

In stoichiometry therein includes

•1. a relative atomic mass is a measurement of the mass of an atom relative to the mass of 1 carbon-12 atom

•2. The relative molecular mass is the sum of the mass of the entire atomic mass making up the molecule or is the sum of the relative atomic masses that make up the molecule

•3. Mol is a unit of the number of particles where 1 mole is the number of particles contained in a substance which is equal to many atoms in 12 gr C-12

1 mol = 6.0210²³ particles

V = n × Vm

V = volume of gas, liter

n = mole

Vm = molar volume (liters / mol)

Molar volume depends on conditions:

Conditions at T 0 ° C and P 1 atm

VM is 22.4 liters/mol.

Conditions at T 25 ° C and P 1 atm Vm in this condition = 24.4 liters / mol

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element (Ar) or the relative molecular mass (Mr)

mole = gram / (Ar / Mr)

Reaction that happened

Cu(s) + 2 AgNO₃ → Cu(NO₃)₂ + 2Ag.

known 4 grams of silver nitrate AgNO ₃

From the reaction, equation shows the reaction coefficients of Cu and AgNO₃ = 1: 2 so that the mole ratio of both is also 1: 2

We specify the mole of AgNO₃

relative molecular mass AgNO₃ = 170

so mole AgNO3 = 4/170

= 0.0235

so that

mass = 0.0235./2 . relative atom mass

= 0,0118 . 63.5

= 0,7493 grams

convert 15.0 g Al to AlBr3

link

methane gas (CH₄) is combusted

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the mass of 3.4 moles of nitric acid (HNO₃)

link

the mass of excess reagent

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Keywords: Stokiometry, mole, grams, AgNO₃

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >