How much cesium (half-life = 2 years) would remain from a 10 g sample after 4 years?
O A. Og
OB. 8g
O c. 59
O D. 29
SUBMIT

2.5 grams

Explanation:

Expression for rate law for first order kinetics is given by:

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) to calculate the rate constant:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

b) to find amount left after 4 years

Thus 2.5 g of cesium would remain from a 10 g sample after 4 years

43.452

step-by-step explanation:

284 times .153 = 43.452