When an F atom becomes an F-ion, the Fatom gains a proton
gains an electron
loses an electron
loses a proton

When an F atom becomes an F-ion, the F atom gains an electron.

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The Fluoride ion given has a -ve charge onto it. Thus in order to become stable Fluorine gains an electron. Thus option b is correct.

The elements in the periodic table try to attain the stable noble gas configuration in the order to become stable. The noble gas configuration has the elements to be less reactive.

When the atom loses an electron in order to become more stable,  a +ve charge has been implemented onto the ion.

When the atom gains an electron to become stable, a -ve charge has been added to the ion.

The Fluoride ion given has a -ve charge onto it. Thus in order to become stable Fluorine gains an electron. Thus option b is correct.

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n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

it's filtration, but this is an assumption so my apologies if i got this