In the activity, click on the Keq and ΔG∘ quantities to observe how they are related. Calculate ΔG∘using this relationship and the equilibrium constant (Keq) obtained in Part A at T=298K:Keq=1.24×1020Express the Gibbs free energy (ΔG∘) in joules to three significant figures.

The Gibbs free energy of the reaction is -114629.4 J

Explanation:

To calculate the Gibbs free energy of the reaction, we use the equation:

where,

= Gibbs free energy of the reaction = ?

R = Gas constant =

T = temperature of the reaction = 298 K

= equilibrium constant of the reaction =

Putting values in above equation, we get:

Hence, the Gibbs free energy of the reaction is -114629.4 J

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.