Chemistry, 10.06.2020 09:57 ameliaxbowen7

50.0 g N204 (92.02 g/mol) react with 45.0 g N2H4 (32.05 g/mol) forming nitrogen gas, N2 (28.01 g/mol) and water, H20 (18.02 g/mol). What mass in grams of excess-reactant is
left over?

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50.0 g N204 (92.02 g/mol) react with 45.0 g N2H4 (32.05 g/mol) forming nitrogen gas, N2 (28.01 g/mo...

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