In the reaction: CO3²- + H+ --> HCO³-
The CO3²- ion is considered a base because it
1) accepts a proton
2) accepts an electron
3) donates a proton
4) donates an electron
Thanks! :)

1) accepts a proton

Explanation:

CO₃⁻²  is a base here because it is accepting a proton ( H⁺) through coordinate bonding by donating a pair of electron .

So option (1) is correct .

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

може ли да зареждате повече информация, моля