Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. C + Fe ₂ O ₃ → CO ₂ + Fe

3C + 2Fe ₂ O ₃ → 3CO ₂ + 4Fe

Explanation:

C + Fe ₂ O ₃ → CO ₂ + Fe

Left Side

C = 1

Fe = 2

O = 3

Right Side

C = 1

Fe = 1

O = 2

So we can see that while Carbon is balanced Fe and O are not.

We then attempt to balance the equation by balancing the Oxygen.

C + 2Fe ₂ O ₃ → 3CO ₂ + Fe

Left Side

C = 1

Fe = 4

O = 6

Right Side

C = 3

Fe = 1

O = 6

Oxygen is now balanced but C and Fe are not, though this is an easy fix as each are independent on each side of the equation.

3C + 2Fe ₂ O ₃ → 3CO ₂ + 4Fe

Left Side

C = 3

Fe = 4

O = 6

Right Side

C = 3

Fe = 4

O = 6

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in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.