Need help with these 7 problems

1. 2.3

2. 4.5

3. 10.5

4. 5.6

5. 3.5

6. 3.9

7. 1.6

Explanation:

pH = - log [H+]

1. Lemon juice

[H+] = 0.005

pH = - log [H+]

pH = - log 0.005

pH = 2.3

2. Beer

[H+] = 3.16x10^-5

pH = - log [H+]

pH = - log 3.16x10^-5

pH = 4.5

3. Milk of Magnesia

[H+] = 3.16x10^-11

pH = - log [H+]

pH = - log 3.16x10^-11

pH = 10.5

4. Rain water

[H+] = 2.51x10^-6

pH = - log [H+]

pH = - log 2.51x10^-6

pH = 5.6

5. Soda

[H+] = 3.16x10^-4

pH = - log [H+]

pH = - log 3.16x10^-4

pH = 3.5

6. Tomatoes

[H+] = 1.23x10^-4M

pH = - log [H+]

pH = - log 1.23x10^-4

pH = 3.9

7. Bleach

[OH-] = 2.3x10^-2M

pOH = - log [OH-]

pOH = - log 2.3x10^-2

pOH = 1.6

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.