Sodium metal and water react to form hydrogen and sodium hydroxide. If 11.96 g of sodium react with water to form 0.52 g of hydrogen and 20.80 g of sodium hydroxide, what mass of water was involved in the reaction

9.36g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction.

2Na + 2H2O —> 2NaOH + H2

Next, we shall determine the mass of Na and H2O that reacted from the balanced equation.

This is illustrated below:

Molar mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

46g of Na reacted with 36g of H2O.

Now, we can determine the mass of H2O involved in reaction as follow:

From the balanced equation above,

46g of Na reacted with 36g of H2O.

Therefore, 11.96g of Na will react with = (11.96 x 36)/46 = 9.36g of H2O.

Therefore, 9.36g of H2O were used for the reaction.

answer; i believe that the correct answer is (a) potassium(k)

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.