516 mL of a 3.82 M sodium sulfate (Na2S04) solution is diluted with 0.875 L of water. What is the new concentration in molarity?

1.42 M

Explanation:

In this case have a dilution problem, therefore we need to use the dilution equation:

What values we have?

Now, we can calculate if we add the volumes, so:

So,  

We can plug the values in the equation:

I hope it helps!