Select the precipitate that forms when aqueous ammonium sulfide reacts with aqueous copper(ii) nitrate. refer to the solubility rules. Provide the complete ionic equation, net ionic equation and spectator ions for https://tex. z-dn. net/?f=%28NH_4%29_2S%28aq.%29%2BCu% 28NO_3%29_2%28aq.%29%5Crightarrow%2 0CuS%28s%29%2B2NH_4NO_3%28aq.%29

- The precipitate that forms from the reaction of Ammonium Sulfide and Copper (II) Nitrate is the insoluble Copper (II) Sulfide (CuS).

- Overall ionic equation

2NH₄⁺ + S²⁻ + Cu²⁺ + 2NO₃⁻ → 2NH₄⁺ + 2NO₃⁻ + CuS (s)

- Net Ionic equation

S²⁻ + Cu²⁺ → CuS (s)

Or better written as

Cu²⁺ + S²⁻ → CuS (s)

Spectator ions include 2NH₄⁺ and 2NO₃⁻.

Explanation:

Ammonium Sulfide - (NH₄)₂S

Copper (II) Nitrate - Cu(NO₃)₂

The overall equation for this reaction is a double displacement reaction and the balance form is represented by

(NH₄)₂S (aq) + Cu(NO₃)₂ (aq) → 2NH₄NO₃ (aq) + CuS (s)

Copper (II) Sulfide (CuS) is the insoluble precipitate formed from this reaction.

Note that the compounds in aqueous form are the ones that can allow the existence in ionic form, the insoluble solid compound stays in that form without ionizing, hence, the overall ionic equation is

2NH₄⁺ + S²⁻ + Cu²⁺ + 2NO₃⁻ → 2NH₄⁺ + 2NO₃⁻ + CuS (s)

Then, the ions that occur on both sides of the overall ionic equation, are called spectator ions and they include 2NH₄⁺ and 2NO₃⁻.

These spectator ions can then cancel out, leaving us with the net ionic equation

S²⁻ + Cu²⁺ → CuS (s)

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atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8