How much heat will be absorbed by 122 g of water when its temperature is raised by 17oC? The specific heat for water is 4.18 J/g oC. Use significant figures.

Heat energy = 8669.32J

Explanation:

Mass = 122g

Change in temperature ∇T = 17°C

Specific heat capacity (c) = 4.18J/g°C

Heat energy (Q) = ?

Heat energy (Q) = mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

Q = mc∇T

Q = 122 × 4.18 × 17

Q = 8669.32J

The heat energy required to raise 122g of water by 17°C is 8669.32J

Explanation:

Hello,

In this case, we can compute the absorbed heat of water needed to raise its temperature by 17 °C by using the following formula:

In this case, the mass is 122 g, the specific heat 4.18 J/(g°C) and the temperature change 17 °C, hence the heat turns out:

Best regards.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.