10) Intravenous saline solutions have a concentration of 1.5 M NaCl. How many liters of saline can be prepared from 50.0 g of NaCl?

0.57 mol/L

Explanation:

Molarity (M) is defined as the number of moles of solute per liter of solution (moles/Liter).

Molarity  =   or Moles  =  molarity × litres

so, the mass of Nacl in 1 mol is 58.44 g,

Moles of NaCl = 50.0g x 1 mole NaCl / 58.44 g

                          = 0.855 mol NaCl

Moles  =  molarity × litres

0.855 = 1.5 M x L

L = 0.57 mol/L

Hence, 0.57 mol/L can be prepared from 50.0 g of NaCl.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.