How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of calcium metal? (2 points) Ca (s) + 2HCl (aq)yields CaCl2 (aq) + H2 (g) Select one: a. 1200 mL b. 2400 mL c. 3750 mL d. 9600 mL

Asolution is made by dissolving 2.3 moles of sodium chloride (nacl) in 0.155 kilograms of water. if the molal boiling point constant for water (kb) is 0.51 °c/m, what would be the boiling point of this solution? show all the steps taken to solve this problem.