At standard temperature and pressure 1 mole of any gas has a volume of 22.4 liters of gas. If the 5 grams of baking soda reacted at standard temperature and pressure, what volume of gas would be produced?

1.33L of gas

Explanation:

1 mole of Baking soda (NaHCO₃) reacts with acetic acid producing 1 mole of CO₂, water and sodium acetate, thus:

NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂

5g of NaHCO₃ (Molar mass: 84g/mol) are:

5g × (1mol / 84g) = 0.0595 moles of NaHCO₃ that produce 0.0595 moles of CO₂ -Moles of gas-.

If 1 mole of gas occupies 22.4L, 0.0595 moles occupy:

0.0595 moles gas × (22.4L / mol) = 1.33L of gas

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol