A 0.125L solution of NaOH is neutralized by 0.0425L of a 0.65 M H2SO4 solution. What is the concentration of the NaOH solution?

0.442 M

Explanation:

The equation of the reaction must first be written down before the problem can be correctly solved.

2NaOH(aq) + H2SO4(aq) > Na2SO4(aq) + 2H2O(l)

Given that;

Concentration of acid CA= 0.65 M

Concentration of base CB=

Volume of acid CA= 0.0425L

Volume of base CB= 0.125L

Number of moles of acid = 1

Number of moles of base = 2

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CB= CAVANB/VBNA

Substituting values;

CB= 0.65 × 0.0425 × 2 / 0.125 × 1

CB= 0.442 M

you gotta add the following molecules so we can give u an answer

explanation:

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.