Which element in each pair has larger ionization energy (circle)?
a) Be or Ba b) Cu or Ra c) Kor
V d ) W or Cr

a. Beryllium (Be) has a larger ionization energy.

b. Copper (Cu) has a larger ionization energy.

c. Vanadium (Va) has a larger ionization energy.

d. Tungsten (W) has a larger ionization energy.

Ionization energy can be defined as the minimum energy required to remove (detach) an electron from a neutral atom in its gaseous state.

In Chemistry, ionization energy generally tend to increase from left to right across a period on the periodic table and from bottom to top in each group of a periodic table.  

Given the following pair of elements:

a. Beryllium (Be) or Barium (Ba).

The ionization energy of beryllium (Be) is 900 kJ/mol.

The ionization energy of barium (Ba) is 503 kJ/mol.

Thus, beryllium (Be) has a larger ionization energy.

b. Copper (Cu) or Radium (Ra)

Thus, copper (Cu) has a larger ionization energy.

c. Potassium (K) or Vanadium (Va)

Thus, vanadium (Va) has a larger ionization energy.

d. Tungsten (W) or Chromium (Cr)

Thus, tungsten (W) has a larger ionization energy.

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see explanation

Explanation:

a) Be

b) Cu

c) V

d) Cr

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c

explanation: