For the reaction 2H₂(g) + O₂(g) → 2H₂O(g), what volume of water vapor can be made from 100 grams of oxygen gas and an excess of hydrogen at STP? Please show work.

140 L

Explanation:

Step 1: Write the balanced equation

2 H₂(g) + O₂(g) → 2 H₂O(g)

Step 2: Calculate the moles corresponding to 100 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

Step 3: Calculate the moles of water vapor formed

The molar ratio of oxygen to water vapor is 1:2.

Step 4: Calculate the volume corresponding to 6.26 moles of water vapor

1 mole of any ideal gas under STP has a volume of 22.4 L.

im not exactly sure but i think its b!

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.