Balance the following reaction CS2+Cl2. CCl4+S2Cl2

CS₂ + 3Cl₂ ⇒ CCl₄ + S₂Cl₂

Explanation:

This one is relatively simple. When we take inventory of both sides, we see 1 Carbon, 2 Sulfurs, and 2 Chlorines on the reactant side, and 1 Carbon, 2 Sulfurs, and 6 Chlorines on the product side. Since we have Cl₂ on the left and we want 6 on the left, let's add a coefficient of 3 to Cl₂. This balances everything out! Final CS₂ + 3Cl₂ ⇒ CCl₄ + S₂Cl₂. Hope this helps!