0.82 moles of water at 25 C absorbs 273 Joules of heat in my kitchen the day my AC was broken. What was the final temperature of the water? Specific heat of water = 4.184 J/g C.

Please show work too

Formulas if necessary: q = mc (Delta T) where c = specific heat of water= 4.184 J/gC

Final temperature is 29.42 °C

Explanation:

Mass of water = Number of moles × Molar mass

= 0.82 × (2(1) + 16)

= 0.82 × 18

= 14.76 g

Q=mcΔT. *let's say final temperature is x

273 = 14.76 × 4.184 × ( x - 25 )

273 = 61.76 × ( x - 25 )

273 = 61.76x - 1544

273 + 1544 = 61.76x

1817 = 61.76x

x = 29.42 °C

So the final temperature is 29.42 °C (. ❛ ᴗ ❛.)

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