The pressure and temperature inside a bike tires 10 ATM and 10 K receptively. What will the pressure be come in the tire when the temperature is increased to 20 K

P = 20atm

Explanation:

P1 = 10atm

T1 = 10K

P2 = ?

T2 = 20K

This question requires the use of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided its volume remains constant

Mathematically,

P = kT, k = P / T

P1 / T1 = P2 / T2 = P3 / T3==Pn / Tn

P1 / T1 = P2 / T2

P2 = (P1 × T2) / T1

P2 = (10 × 20) / 10

P2 = 20atm

The final pressure of the gas is 20atm

h let me think

the temperature of the gas, in k, not celsius.