A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:

HNO3(aq) + NaOH (aq) → NaNO3(aq) + H2O(1)

How many moles of HNO3 are in the sample?

2.5x10^–3 mole.

Explanation:

Data obtained from the question include:

Volume of solution = 25mL

Molarity of HNO3 = 0.1M

Mole of HNO3 =..?

First, we'll begin by converting 25mL to L. This can be achieved by doing the following:

1000mL = 1L

Therefore, 25mL = 25/1000 = 0.025L

Now, we can obtain the number of mole of HNO3 present in the solution as follow:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.1 x 0.025

Mole = 2.5x10^–3 mole.

Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

your answer would be “dry”