The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.4 g/mol), is soluble in benzene C6H6.

How many grams of estrogen are needed to generate an osmotic pressure of 4.45 atm when dissolved in 234 ml of a benzene solution at 298 K.

grams estrogen

  11.6g of estrogen are needed to generate an osmotic pressure of 4.45 atm when dissolved in 234 ml of a benzene solution at 298 K.

Explanation:

To calculate the amount of solute, we use the equation for osmotic pressure, which is:

Or,

where,

= osmotic pressure of the solution = 4.45 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Let Mass of solute (estrogen)  = x g  

Volume of solution = 234 mL

R = Gas constant =

T = temperature of the solution =

Putting values in above equation, we get:

Hence, 11.6g of estrogen are needed to generate an osmotic pressure of 4.45 atm when dissolved in 234 ml of a benzene solution at 298 K.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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