He volume of N2 gas is 500 mL at the temperature of 10 ℃ at 108 kPa. What will be the new pressure if the volume increased to 750 mL and the temperature increased at 21 ℃? Please quickly help

The new pressure will be 74.8 kPa

Explanation:

Step 1: Data given

Volume of the N2 gas = 500 mL = 0.500 L

Temperature = 10.0 °C = 283 K

Pressure = 108 kPa

The volume is increased to 750 mL = 0.750 L

The temperature is increased to 21.0 °C = 294 K

Step 2: Calculate the new pressure

P1*V1 / T1 = P2*V2 / T2

⇒with P1 = the initial pressure = 108 kPa

⇒with V1 = the initial volume = 0.500 L

⇒with T1 = the initial temperature = 283 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 0.750 L

⇒ with T2 = the increased temperature = 294 K

108 * 0.500 / 283 = P2 * 0.750 / 294

P2 = (108*0.500 * 294) / (283*0.750)

P2 = 74.8 kPa

The new pressure will be 74.8 kPa