79. Methane, the chief component of natural gas, burns in oxygen according to the equation
CH,(g) + 2 0,(g) » CO,(g) + 2 H2O(g)
If 7.0 mol of CH, react with an unlimited amount of oxygen, what amount (in moles) of
H2O(g) will be produced?

14 mol

Explanation:

                                CH4(g) + 2O2(g) » CO2(g) + 2H2O(g)

from reaction          1 mol                                                2 mol

given                       7 mol                                                x mol

x = (7*2)/1 = 14 mol