Given the following equilibrium:
2H2(g) + S2(g) = 2H2S(g)
For a certain reaction at equi...
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Chemistry, 10.05.2020 16:57 alyssacyamamoto8050
Given the following equilibrium:
2H2(g) + S2(g) = 2H2S(g)
For a certain reaction at equilibrium at 700°C, analysis shows
there to be 2.50 moles of H2, 1.35 x 10-5 moles of S2, and
8.70 moles of H2S present in a 12.0-L flask. Calculate the
equilibrium constant (Keg).
a
1.08 x 10^9
b
1.09 x 10^8
C
1.08 x 10^7
d
1.07 x 10^6
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