What volume would 32.0 g of NO2 gas occupy at 3.12 atm and 18.0 Celsius

Volume of 32.0 g at 3.12 atm and 18.0 is 5.33 L.

Explanation:

Molar mass of = 46.0055 g/mol

So, 32.0 g of = mol of = 0.696 mol of

Let's assume behaves ideally.

Then    , where P, V, n, R and T represents pressure, volume, number of moles, gas constant and temperature (in kelvin scale) respectively.

Here = 3.12 atm, = 0.696 mol, R = 0.0821 L.atm/(mol.K) and T = (273+18.0)K = 291 K

So,      

        or,

        or,

So, volume of 32.0 g at 3.12 atm and 18.0 is 5.33 L.

hi,

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number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.