Suppose you want to extract the iron from ferrous iodide, FeI2, through electrolysis. What can be said about the merits of electrolysis of molten versus aqueous FeI2? Group of answer choices You'll have to perform electrolysis of the aqueous solution because you can't get iron metal from electrolysis of the molten salt. You'll have to perform electrolysis on the molten salt because you can't get iron metal from electrolysis of the aqueous solution. Electrolysis of either the molten or aqueous salt will produce solid iron. Electrolysis will not produce solid iron rega

Electrolysis of either the molten or aqueous salt will produce solid iron.

Explanation:

Iron (II) iodide has a relatively low melting point. Electrolysis of the molten salt will probably produce solid metallic iron and liquid I2 as well as iodine vapor. The temperature need not be high enough to cause Fe to melt.

so Electrolysis of either the molten or aqueous salt will produce solid iron.

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.

the answer is minerals.