The constant pressure molar heat capacity, C_{p, m}C p, m , of methane gas, CH_4CH 4 , is 35.31\text{ J K}^{-1}\text{ mol}^{-1}35.31 J K −1 mol −1 at temperatures close to 298\text{ K}298 K. Calculate the enthalpy change when 1.6\text{ kg}1.6 kg of methane gas is heated from a temperature of 280\text{ K}280 K to 320\text{ K}320 K.

Explanation:

Constant pressure molar heat capacity Cp = 35.3 J / mol

Enthalpy change of the given process can be calculated as follows

ΔH = n Cp x Δt , n is number of mole , Cp is molar heat capacity and Δt

is change in temperature.ΔH is enthalpy change.

Putting the values

ΔH = n Cp x Δt

mol weight of methane = 16

1.6 kg = 1600 g

= 1600 / 16

= 100 moles

n = 100

Putting the values

ΔH = n Cp x Δt

= 100 x 35.3 x ( 320 - 280 )

= 141200 J

= 141.2 KJ .

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole