?_N2 + _? O2 → _?_ NO2 balance the equation and determine the correct lowest mole ratio.
If 5 moles of N2 reacted with 12 moles O2

How many moles NO2 are produced?
How many moles of O2 are left ? How many moles of N2 are left?

NO2 produced = 5 moles

O2 left = 7 moles

N2 left = 0 moles

Explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

i think that the answer is c