Consider the following balanced reaction:
4NH3 (g) + 502 (g) – 4NO (g) + 6H20 (g)
How many grams of ammonia are required to react completely with 40 g of oxygen?
A. 154
B.
179
C. 34 g
D.
19 g

17g

Explanation:

4NH3 (g) + 502 (g) –> 4NO (g) + 6H20 (g)

Mass of O2 mole = 32g

Therefore 5O2 = 160g

Mass of NH3 mole = 17g

Therefore 4NH3 = 17 x 4 =68g

Required amount of NH3 = 68 x 40/160 = 17g

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.