How much energy is released when 50.00 mol of glycerin melts? (Heat of fusion glycerin-91.7 KJ/mol)

4585 KJ

Explanation:

Data obtained from the question. This includes following:

Number of mole (n) of glycerin = 50 moles

Heat of fusion glycerin (Hf) = 91.7 KJ/mol

Heat (Q) released =?

The heat released can be obtained as follow:

Q = n•Hf

Q = 50 x 91.7

Q = 4585 KJ

Therefore, 4585 KJ of heat is released.

output?

explanation:

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o