How many moles of sodium are required to produce 40. grams of NaOH? *

2Na + 2H20 (arrow) 2NaOH +H2

.25 moles
.50 moles
1.0 mole
2.0 moles

1.0 mole of sodium

Explanation:

40.0 g NaOH  x __1 mol__ x __2 mol Na__ = 1 mol of Na

                            39.999 g      2 mol NaOH

0

explanation:

488479

rvmoo+478)9.68

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :