Since dilute NaOH (ltd. OH-) and dilute aqueous NH3 produce similar results, why do the results differ between excess NaOH (xs. OH-) and concentrated aqueous NH3? Question 2 options: The results differ because the ammonia (when added in excess amounts) can form a neutral complex with the metal ions, and this complex differs in color from the anionic complex with the hydroxide ions. The results differ because the ammonia (when added in excess amounts) does not react with the metal ions. The results differ because the ammonia (when added in excess amounts) can form an anionic complex with the metal ions, and this complex differs in color from the cationic complex with the hydroxide ions. The results differ because the ammonia (when added in excess amounts) can form a neutral complex with the metal ions, and this complex differs in color from the cationic complex with the hydroxide ions.