In recent years engineers have been working on an aluminum-air battery as an alternative energy source for electric vehicles. The battery consists of an aluminum anode, which is oxidized to solid aluminum hydroxide, immersed in an electrolyte of aqueous KOH. At the cathode oxygen from the air is reduced to hydroxide ions on an inert metal surface. Write the two half-reactions for the battery. Please include all states of matter

The anode is oxidized and the cathode is reduced, in this way we are facing a redox reaction or oxide reduction.

Where the oxygenated compound oxidizes, and the protonized reduces.

Explanation:

When he says that oxygen is reduced the reaction would be:

OXYGEN + H (+1) > OH-

And the reaction where solid aluminum hydroxide is formed will be:

Al (+3) + 3 KOH (aqueous) > Al (OH) 3 (solid) + 3 K (+1),

Here we see how aluminum is immersed in an aqueous medium and becomes a solid compound in the form of hydroxide, where when attached to an oxygen, it is oxygenated and oxidized.

This reaction is considered irreversible

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.