If 54.9 L of an ideal gas is cooled from 64 degrees C to 7 degrees C, what will the volume of the gas become?

Volume = 45.62L

Explanation:

Data;

V1 = 54.9L

T1 = 64°C = (64 + 273.15)k = 337.15K

T2 = 7°C = (7 + 273.15)k = 280.15K

V2 = ?

From Charles law,

The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant

V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 == Vn / Tn

(54.9 / 337.15) = (V2 / 280.15)

V2 = (54.9 * 280.15) / 337.15

V2 = 45.618L

V2 = 45.62L

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.

c. is the answer

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