Galvanic cell is powered by the following redox reaction: (g) (aq) (l)(aq) (s) (aq) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. cl2

Explanation:

1. the 1/2 reaction that occurs at the cathode

3Cl2(g) +6e^- > 6Cl^- (aq)

2 the 1/2 reaction that occurs at the anode

2MnO2(s) + 8OH^-(aq) > 2MnO4^- (aq) + 4H2O(l) +6e^-      

2MnO2(s) + 8OH^-(aq) > 2MnO4^- (aq) + 4H2O(l) +6e^-

E0 = -0.59v

3Cl2(g) +6e^- > 6Cl^- (aq)                                                  

E0 = 1.39v

3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)  

E0cell = 0.80v

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

i believe it is a.) released into

explanation: