Calculate Z and V for ethylene at 25°C and 12 bar by the following equations: (a) The truncated virial equation [Eq. (3.38)] with the following experimental values of virial coefficients: B = −140 cm3·mol−1 C = 7200 cm6·mol−2 (b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)] (c) The Redlich/Kwong equation (d) The Soave/Redlich/Kwong equation (e) The Peng/Robinson equation

Following are the solution to the given points:

Given:

To find:

points=?

Solution:

a)

Given:  

(b)  

(c)  

For Redlich/Kwong EOS:  

Calculating the value of Z and by assume:

Given:

Finding the value of z:  

(d)  

For SRK EOS:  

 Given:

Finding the value of z:

(e)

For Peng/Robinson EOS:

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a = 0.929

b= 0.932

d= 1918cm³/mol

Explanation:

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.