Chemistry, 05.05.2020 14:56 phillipfruge3

What is the freezing point of a 0.82 m aqueous solution of a non-volatile non-electrolyte?

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Answer from: batmandillon21

-1.5 °C

Explanation:

The freezing-point depression is a colligative property, that is, the property of a solution. The freezing point of a solution is lower than the freezing point of the pure solvent. We can find the freezing-point depression of a solution of a non-volatile non-electrolyte solute using the following expression.

$\Delta T_f = K_f \times b$

where,

$\Delta T_f$ : the freezing-point depression K_f

: cryoscopic constant (For water, Kf = 1.86 °C/m)

: molality

$\Delta T_f = \frac{1.86\°C}{m} \times 0.82m = 1.5\°C$

The freezing-point of pure water is 0°C. The freezing-point of the solution is:

$0\°C-1.5\°C = -1.5\°C$

Answer from: Quest

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

Answer from: Quest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be $^{9}_{5}be^{-}$ and $^{9}_{4}be$ .

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.

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What is the freezing point of a 0.82 m aqueous solution of a non-volatile non-electrolyte?

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