A gas has a volume of 1.6 liters at STP. What is the new volume when the temperature is
changed to 60K and the pressure stays constant at 1.0 atm?

0.35L

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 1.6L

Initial pressure (P1) = stp = 1atm

Initial temperature (T1) = stp = 273K

Final temperature (T2) = 60K

Final pressure (P2) = constant (the same as initial pressure)

Final volume (V2) =?

Step 2:

Determination of the new volume of the gas.

Considering the question given, the gas is obeying Charles' law since the pressure is constant. Thus, the final volume i.e the new volume of the gas can be obtained as follow:

V1/T1 = V2/T2

1.6/273 = V2/60

Cross multiply to express in linear form

273 x V2 = 1.6 x 60

Divide both side by 273

V2 = (1.6 x 60) /273

V2 = 0.35L

Therefore, the new volume of the gas is 0.35L

the answer is barium and copper bromide

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole