Chemistry, 04.05.2020 23:04 ashcookie27

Copper reacts with silver nitrate through single replacement.
If 2.60 g of silver is produced from the reaction, how many moles of copper(II) nitrate are also produced?

Answers: 1

Show answers

Answers

Answer from: dooboose15

Approximately $0.121\; \rm mol$ .

Explanation:

Balance the equation

$\rm Cu\; (s)$ reacts with $\rm AgNO_3\; (aq)$ to produce $\rm Ag\; (s)$ and $\rm Cu(NO_3)_2\; (aq)$ .

$\rm ? \; Cu\, (s) + ?\; AgNO_3\, (aq) \to ?\; Ag\, (s) + ?\; Cu(NO_3)_2\, (aq)$ .

To balance this equation, start by setting the coefficient of the most complex species to . For example, $\rm Cu(NO_3)_2\, (aq)$ has more atoms in each of its formula unit than any other species in this reaction. Let the coefficient of

$\rm ? \; Cu\, (s) + ?\; AgNO_3\, (aq) \to ?\; Ag\, (s) + 1\; Cu(NO_3)_2\, (aq)$ .

That formula unit of $\rm Cu(NO_3)_2\, (aq)$ would include:

$1 \times 1 = 1$ $\rm Cu$ atom, $1 \times 2= 2$ $\rm N$ atoms, and $1 \times 2 \times 3 = 6$ $\rm O$ atoms.

The other product, $\rm Ag\; (s)$ , contains neither $\rm Cu$ atoms nor $\rm N$ atoms. Therefore, the product side would include exactly

one $\rm Cu$ atom, two $\rm N$ atoms, andsix $\rm O$ atoms.

Atoms are conserved in a chemical reaction. The reactant side shall also include:

$1 \times 1 = 1$ $\rm Cu$ atom, $1 \times 2= 2$ $\rm N$ atoms, and $1 \times 2 \times 3 = 6$ $\rm O$ atoms.

Among the reactants, $\rm AgNO_3\, (aq)$ is the only source of $\rm N$ atoms. Each formula unit of

Similarly, the coefficient of $\rm Cu$ would be 1/ 1 = 1 .

$\rm 1 \; Cu\, (s) + 1\; AgNO_3\, (aq) \to ?\; Ag\, (s) + 1\; Cu(NO_3)_2\, (aq)$ .

There would be exactly $\rm Ag$ atom on the reactant side (from $\rm AgNO_3\, (aq)$ .) The products should also include

Hence the equation:

$\rm 1 \; Cu\, (s) + 1\; AgNO_3\, (aq) \to 2\; Ag\, (s) + 1\; Cu(NO_3)_2\, (aq)$ .

Calculate n(Cu(NO₃)₂ (aq))

The ratio between the coefficients of $\rm Cu(NO_3)_2\; (aq)$ and $\rm Ag\, (s)$ is:

$\displaystyle \frac{n(\mathrm{Cu(NO_3)_2\, (aq)})}{n(\mathrm{Ag\, (s)})} = \frac{1}{2}$ .

Rearrange this equation to obtain:

$\displaystyle n(\mathrm{Cu(NO_3)_2\, (aq)}) = \frac{1}{2} \, n(\mathrm{Ag\, (s)})$ .

In other words, $n(\rm Cu(NO_3)_2\; (aq))$ (the number of moles of $\rm Cu(NO_3)_2\; (aq)$ that is produced) can be found from $n(\mathrm{Ag\, (s)})$ (the number of moles of $\rm Ag\, (s)$ that is produced.)

On the other hand, $n(\rm Ag\; (aq))$ can be found from $m(\rm Ag\; (s))$ (the mass of $\rm Ag\, (s)$ that is produced) using $M(\rm Ag)$ (the formula mass of $\rm Ag$ .)

Look up relative atomic mass data of $\mathrm{Ag}$ on a modern periodic table:

$\rm Ag$ : 107.868

Therefore, the relative atomic mass of $\rm Ag\, (s)$ would be:

$M(\rm Ag) = 107.868\; \rm g \cdot mol^{-1}$ .

Calculate $n(\rm Ag\; (s))$ :

$\begin{aligned}& n({\rm Ag\, (s)}) \\ &= \frac{m(\mathrm{Ag\, (s)})}{M(\mathrm{Ag})}\\ &=\frac{2.60\; \rm g}{107.868 \; \rm g \cdot mol^{-1}} \\ &\approx 0.0241035\; \rm mol \end{aligned}$ .

Calculate $n(\rm Cu(NO_3)_2\; (aq))$ :

$\displaystyle n(\mathrm{Cu(NO_3)_2\, (aq)}) = \frac{1}{2} \, n(\mathrm{Ag\, (s)}) \approx 0.0121\; \rm mol$ .

Answer from: Quest

Sorry i dont understand the question can you rephase it?

Answer from: Quest

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.