A sample of nitrogen gas occupies 1.55 L at
27.0°C and 1.00 atm. What will the volume be at
−100.0°C and the same pressure?
(2 Points)
0.894 L
0.998 L
0.58 L

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

the dissolution of polymer can be thermodynamically described in 2 steps.

the answer is d.) potassium