Chemistry, 05.05.2020 07:20 stphdrn4347

Onsider the reversible dissolution of lead(II) chloride. P b C l 2 ( s ) − ⇀ ↽ − P b 2 + ( a q ) + 2 C l − ( a q ) PbClX2(s)↽−−⇀PbX2+(aq)+2ClX−(aq) Suppose you add 0.2393 g of P b C l 2 ( s ) PbClX2(s) to 50.0 mL of water. When the solution reaches equilibrium, you find that the concentration of P b 2 + ( a q ) PbX2+(aq) is 0.0159 M and the concentration of C l − ( a q ) ClX−(aq) is 0.0318 M. What is the value of the equilibrium constant, Kc, for the dissolution of P b C l 2 PbClX2?

Answers: 3

Show answers

Answers

Answer from: lekaje2375

$K_c=9.34*10^{-4}$

Let's solve this question step by step:

Step 1:

The balanced equation for the reaction.

PbCl_2(s) ⇌ $Pb^{2+} (aq)+2Cl^-(aq)$

Given that:

Mass of PbCl₂ = 0.2393 g

Volume = 50mL

Concentration of $[Pb^{2+}]$ = 0.0159 M

Concentration of [Cl^-] = 0.0318 M

To find:

Equilibrium constant, Kc =?

Step 2:

Determination of the number of mole PbCl₂.

The number of moles of PbCl₂ can be calculated as:

Molar Mass of PbCl₂ = 207 + (35.5x2) = 278g/mol

Mass of PbCl₂ = 0.2393 g

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of PbCl_2}= \frac{0.2393}{278} =8.61*10^{-4} moles$ Number of moles of PbCl₂ $=\frac{0.2393}{278} =8.61*10^{-4}moles$

Step 3:

Determination of Molarity of PbCl₂.

Mole of PbCl₂ = $8.61*10^{-4} moles$

Volume = 50mL = 50/1000 = 0.05L

Molarity of PbCl₂ =?

Molarity = mole /Volume

Molarity of PbCl₂ = $\frac{8.61*10^{-4}moles}{0.05 L} =0.0172M$

Molarity of PbCl₂ = 0.01722 M

Step 4:

Determination of the equilibrium constant Kc.

PbCl_2(s) ⇌ $Pb^{2+} (aq)+2Cl^-(aq)$

The equilibrium constant Kc for the equation above is given by:

$K_c=\frac{[Pb^{2+}][Cl^-]}{[PbCl_2]} \\\\$

$[Pb^{2+}]$ = 0.0159 M

[Cl^-] = 0.0318 M

[PbCl₂] = 0.01722 M

$K_c=\frac{0.0159*(0.0318)^2}{0.0172} \\\\K_c=9.34*10^{-4}$

The equilibrium constant Kc = $9.34*10^{-4}$

Learn more:

link

Answer from: mayasofia

9.34x10^-4

Explanation:

Step 1:

The balanced equation for the reaction.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

Step 2:

Data obtained from the question:

Mass of PbCl2 = 0.2393 g

Volume = 50mL

concentration of Pb^2+, [Pb^2+] = 0.0159 M

Concentration of Cl^-, [Cl^-] = 0.0318 M

Equilibrium constant, Kc =?

Step 3:

Determination of the number of mole PbCl2.

The number of mole of PbCl2 can be obtained as follow:

Molar Mass of PbCl2 = 207 + (35.5x2) = 278g/mol

Mass of PbCl2 = 0.2393 g

Number of mole =Mass /Molar Mass

Number of mole of PbCl2 = 0.2393/278 = 8.61x10^-4 mole

Step 4:

Determination of Molarity of PbCl2.

At this stage we shall obtain the molarity of PbCl2. This is shown below:

Mole of PbCl2 = 8.61x10^-4 mole

Volume = 50mL = 50/1000 = 0.05L

Molarity of PbCl2 =?

Molarity = mole /Volume

Molarity of PbCl2 = 8.61x10^-4/0.05

Molarity of PbCl2 = 0.01722 M

Step 5:

Determination of the equilibrium constant Kc.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

The equilibrium constant Kc for the equation above is given by:

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

[Pb^2+] = 0.0159 M

[Cl^-] = 0.0318 M

[PbCl2] = 0.01722 M

Kc =?

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

Kc = 0.0159 x (0.0318)^2/ 0.01722

Kc = 9.34x10^-4

Answer from: Quest

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

Answer from: Quest

It’s the energy source of stars

Another question on Chemistry

Chemistry, 22.06.2019 05:00

Type the letter that represents the correct location for each particle type below.

Answers: 1

Answer

Chemistry, 22.06.2019 11:20

Sodium nitrite (nano2) reacted with 2−iodooctane to give a mixture of two constitutionally isomeric compounds of molecular formula c8h17no2 in a combined yield of 88%. draw reasonable structures for these two isomers. click the "draw structure" button to launch the drawing utility. place the two compounds in the appropriate boxes below.

Answers: 1

Answer

Chemistry, 22.06.2019 22:30

What if it is did darwin used to support his theory of evolution

Answers: 1

Answer

Chemistry, 23.06.2019 03:00

In november 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. the chunk of ice was estimated to be 98 mi long, 25 mi wide, and 750 ft thick. a typical backyard swimming pool contains about 24,000 gallons of water. how many of these pools could you fill from the water in this iceberg? (assume the iceberg is a rectangular solid of the above dimensions and consists of water only). express answer in scientific notation.

Answers: 1

Answer

You know the right answer?

Onsider the reversible dissolution of lead(II) chloride. P b C l 2 ( s ) − ⇀ ↽ − P b 2 + ( a q ) + 2...

Questions