A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to −10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.

Mass of tin sample

is ≈ 95.7g

Explanation:

This problem bothers on heat calorimetry/capacity of a substance.

Given data

Specific heat capacity of tin

Cp = 0.227 J/g•°C

Initial temperature of tin θ1= 15°C

Final temperature of tin θ2= -10°C

Heat released Q= 543 J

Mass of tin m=

We know that quantity of heat is given as

Q=mcΔθ

Substituting our given data and solving for mass m we have

543= m*0.227*(-10-15)

543= m*0.227*(-25)

543= - 5.675m

m=543/-5.675

= -95.68

Mass of tin is ≈ 95.7g

What is Quantity of heat?

Quantity of heat is the amount of heat absorbed or given out by a body Q=mcθ

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !