Magnesium ions can be precipitated from seawater by the addition of sodium hydroxide. How much sodium hydroxide in grams must be added to a sample of seawater to completely precipitate the 88.4 mg of magnesium present?

Explanation:

Solution 86P

Here, we have to determine the amount of sodium hydroxide required to precipitate all of the Mg.

Mg2+(aq) +2 NaOH(aq) > Mg(OH)2 (s) + 2Na+(aq)

Therefore

Molar mass of NaOH =39.997 g/mol

Molar mass of Mg =24.305 g/mol

Thus,the conversion factors

g NaOH(aq)= mol NaOH(aq) = g Mg = mol Mg

Thus the amount of sodium hydroxide required

=  88.4 mg of  Mg x x x x...

can you list the answers so i can answer

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