The price of gold on April 15,2000 was $282/t. oz. How much did 100.0cm^3 of gold cost that day if 1.00 t. oz=28.4 grams?

price ($) Au = $ 19183.94

Explanation:

april 15,2000:

∴ price Au = $ 282/t.oz

∴ 1.00 t.oz = 28.4 g

∴ V Au = 100.0 cm³  ⇒  price ($) = ?

∴ δ Au = 19.32 g/cm³

⇒ mass Au = (100.0 cm³)*(19.32 g/cm³)

⇒ m Au = 1932 g

⇒ price ($) = (1932 g Au)*(1.00 t.oz/28.4 g Au)*( $ 282/t.oz)

⇒ price ($) = $ 19183.94

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answer: h+ its less than oh

explanation: