For the following reaction, 6.74 grams of oxygen gas are mixed with excess ammonia. The reaction yields 4.04 grams of nitrogen monoxide. ammonia (g) + oxygen (g) nitrogen monoxide (g) + water (g) What is the theoretical yield of nitrogen monoxide ? grams What is the percent yield of nitrogen monoxide ? %

The theoretical yield is 5.07 grams NO

The percent yield of nitrogen monoxide is 79.7 %

Explanation:

Step 1: Data given

Mass of oxygen gas = 6.74 grams

Molar mass O2 = 32.0 g/mol

Ammonia is in excess

The reaction yields 4.04 grams of nitrogen monoxide

Molar mass of nitrogen monoxide = 30.01 g/mol

Step 2: The balanced equation

4NH3 + 5O2 → 4NO + 6H2O

Step 3: Calculate moles O2

Moles O2 = mass O2 / molar mass O2

Moles O2 = 6.74 grams / 32.0 g/mol

Moles O2 = 0.211 moles

Step 4: Calculate moles NO

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.211 moles O2 we'll have 4/5 * 0.211 = 0.1688 moles NO

Step 5: Calculate mass NO

Mass NO = 0.1688 moles * 30.01 g/mol

Mass NO = 5.07 grams

Step 6: Calculate the percent yield

Percent yield = (actual yield / theoretical yield) * 100 %

Percent yield = (4.04 grams / 5.07 grams ) * 100 %

Percent yield = 79.7 %

The theoretical yield is 5.07 grams NO

The percent yield of nitrogen monoxide is 79.7 %

the role of the microscope world in creating new materials .

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

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since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.