Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. ( 1 ) ClO ( g ) + O 3 ( g ) ⟶ Cl ( g ) + 2 O 2 ( g ) Δ H ∘ rxn = − 122.8 kJ ( 2 ) 2 O 3 ( g ) ⟶ 3 O 2 ( g ) Δ H ∘ rxn = − 285.3 kJ ( 3 ) O 3 ( g ) + Cl ( g ) ⟶ ClO ( g ) + O 2 ( g ) Δ H ∘ rxn = ?

ΔH°rxn = - 162.5 kJ

Explanation:

Hello,

In this case, we use the Hess law to compute the required enthalpy of the reaction for the chlorine with ozone.

1. At first, we invert the original (1) equation in order to place the chlorine at the reactants, so the enthalpy sign is inverted to positive:

Cl ( g ) + 2O2 ( g ) ⟶ClO ( g ) + O3 ( g ) ΔH°rxn = 122.8 kJ

2. Then we do not modify the second reaction:

2O3 ( g ) ⟶ 3O2 ( g ) ΔH°rxn = −285.3 kJ

Next, the add the aforementioned reactions:

Cl ( g ) + 2O2 ( g ) + 2O3 ( g )  ⟶ ClO ( g ) + O3 ( g ) + 3O2 ( g )

In order to obtain (3):

O3 ( g ) + Cl ( g ) ⟶ ClO ( g ) + O2 ( g )

And the enthalpy of reaction results:

ΔH°rxn = 122.8 kJ − 285.3 kJ

ΔH°rxn = - 162.5 kJ

Best regards.

i think its 5049.

i hope this !

50.23 i believe is correct but don't quote me on that.